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Nathan
Lv 5
Nathan asked in Science & MathematicsPhysics · 1 decade ago

Desperately need physics help.?

I need to solve this question quickly: Two speakers are driven by a common oscillator at 860 Hz and face each other at a distance of 1.24 m. Locate the points along a line joining the two speakers where relative minima of the amplitude of the pressure would be expected. (Use v = 343 m/s. Choose one speaker as the origin and give your answers in order of increasing distance from this speaker. Enter 'none' in all unused answer boxes.)

Update:

I have to name 7 points.

Update 2:

Please, don't all answer at once.

1 Answer

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  • 1 decade ago
    Favorite Answer

    λf = c (speed of the wave in m/s)

    λ = Wavelength in meters

    f = frequency in Hz

    λ = 343 m/s / 860 Hz = 0.399 meter, which I think would be the spacing of the peaks or valleys. Rounding to 0.4m, then the points would be 0.0, 0.4, 0.8, 1.2, 1.6, 2.0 and 2.4

    .

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