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A couple trigonometry math question..:)?
1. given f(x) = 2x^2-4x+5, we know its root are
a. real, rational, and equal
b. real, rational, and unequal
c. real, irrational, and unequal
d. imaginary
2. given f(x)= log4 x, then f(8) equals
a. 3/2
b. 2
c. 3
d. 4
and one more:)
3. when simplified, (c/2)- (2/c)/1+(c/2)
a. c
b. c+2/2
c. c-2/c
d. c-2/2
Any help would be helpful please and thank you:)
2 Answers
- Anonymous1 decade ago
1. If you use the Quadratic formula you'll have x = 4 ± sqrt(16 - 40) / 4. The square root of a negative number is an imaginary number, so d) is the answer.
2. y = f(8) = log4(8). What is the number that satisfies 4^x = 8 ? It's 3/2 since 4^(3/2) = 4^(2/2) * 4^(1/2) = 4 * sqrt(4) = 4 * 2 = 8. Option a)
3. (c/2) - (2/c)/1 + (c/2) = (c/2) - (2/c) + (c/2) = c - 2/c. Option c)
- Anonymous1 decade ago
Question 2 is a) because 4^(3/2)=8
Convert your log to an exponential.