CAN SOMEBODY PLZ HELP ME WITH THIS MATH QUESTION?? !!!!?

The left side of the equation is Mrs. Pitt's class and the right side is Mr. Brown. x = number of girls

x + 4 = x (4 more girls in Mrs. Pitt's class than Mr. Brown so this equation just sets that equal)

x - 1 = x + 5 ( five girls moved so the +4 turns to -1 and Mr. Brown gets +5)

2x - 2 = x + 5 ( here I multiplied by 2 on Mrs. Pitt's class to make the equation equal because of the " Now there are twice as many..." part)

x - 2 = 5 ( here i begin to solve for x which is Mr. Brown's class original number of girls if you look at the first equation, the right x gets subtracted from the 2x)

x = 7 (theres your answer, just add two on both sides for the final answer)

Hope this helps!

- Austin

let B= Mr. Brown's class

so let B+4=C Mrs. Pitt's class

2(C-5)=(B+5) for the new girls in each class and the info about 2X as much girls

2(B+4-5)=(B+5) sub what C=

2(B-1)=(B+5) 2*(B-1)

2B-2=B+5 add the 2

2B=B+7 - the B

so B=7

hope that helps :)