Show me how to do this chemistry problem - I need to know how to do it. Thanks!?

the method you need is this.

fist calculate the number of moles of the complete molecules in the solution

for

65.0 mL of 0.150 M Na3PO4

(0.65ml * 0.150mol/L * 1L/1000ml) = x number of moles

now multiply this by the number of ions generated by the molecule, in this case 4

(0.65ml * 0.150mol/L * 1L/1000ml)*4 = ions

bo this for all three of the solutions. good luck!

400.0 mL x 0.320 M NaOH = 12.8 mmol NaOH and 25.6 mmol of ions (12.8 mmol Na^+1 and 12.8 mmol OH^-1)

20.0 mL x 0.450 M BaCl2 = 9.00 mmol BaCl2 and 27.0 mmol of ions (9.0 mmol Ba^+2 and 18.0 mmol Cl^-1)

65.0 mL x 0.150 M Na3PO4 = 9.75 mmol Na3PO4 and 39.0 mmol of ions (29.25 mmol Na^+1 and 9.75 mmol PO4^-3)

ANSWER 65.mL of 0.150 M Na3PO4

0.4000L*0.320m *2= 0.256 m ions this NaOH has the most ions

0.020L*0.450m * 3= 0.027m ions

0.065L * 0.150m *4=0.039m ions