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Calculate the molarity of this please?

A sulfuric acid solution containing 690.7 g of H2SO4 per liter of solution has a density of 1.329 g/cm3.

Calculate the molarity of H2SO4 in this solution.

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  • 1 decade ago
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    Molarity= mol solute/ L soln

    d=m/V (where m=mass and V=volume).

    V=m/d ( rearranged)

    V=690.7 g/1.329 g/cm^3

    V=519.714 cm^3

    where 1 cm^3= 1 mL so,

    V=519.714 mL or 0.519714 L

    690.7 g H2SO4 [1 mol H2SO4 / 98.086 g H2SO4] = 7.0418 mol H2SO4

    Molarity= mol solute/ L soln

    Molarity= 7.0418 mol / 0.519714 L

    Molarity= 13.549 M

    Hope this helped, if it did, please choose best answer. Good luck!

    Source(s): Chem major
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