basic physics question...?

Question

A 1200 kg car moving at 12 m/s collides with a 23000 kg car that is waiting at rest at the traffic light. After the collision, the cars lock together and slide. Eventually the two combined cars are brought to rest by a force of kinetic friction to the rubber tires across the dry asphalt surface.

Update:

calculate the frictional force that brings the locked together cars at rest??

calculate the speed of the locked together cars immediately after the collision?

billrussell42 · Accepted Answer

The initial momentum is 1200 x 12 = 14400 kgm/s
after the collision, the momentum is unchanged, so the velocity is

14400 kgm/s = (1200+23000)V
V = 0.595 m/s (b)

for (a), this cannot be calculated without more information, such as time sliding, or distance sliding. 

.

duffield · Answer

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basic physics question...?

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