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Math (integrals) help?
Determine (g/f)' (2) if f(2) = 4, g(2) = -4, f'(2) = 20, g' (2) = 12
I feel like i am supposed to integrate....but im not getting the right answer....please help
2 Answers
- Anonymous1 decade agoFavorite Answer
The derivative of (g/f) needs to be taken, using the quotient rule this problem can be solved.
Quotient Rule:
d/dx [g(x)/f(x)] = [f(x) g'(x) - g(x) f'(x)] / [f(x)]^2
d/dx [g(2)/f(2)] = [f(2) g'(2) - g(2) f'(2)] / [f(2)]^2
= [(4)(12) - (-4)(20)] / [4]^2
= [128] / 16
= 8
- 1 decade ago
its derivatives (quotient rule), not integrals
lo dhi minus hi dlo over lo lo
--> [low* derivative of high - high*derivative of low] / low squared
[(4*12) - (-4*20)] / 16
that = 8
