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Quick calculus question?

What is the general solution of y''(t)=e^(2t)

Please explain

Thanks!

1 Answer

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  • Anonymous
    1 decade ago

    Not really sure what you mean by "general solution" but,

    y'(t) = 2e^(2t)

    and

    y''(t) = 4e^(2t)

    Hope this helps.

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