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Sum of series using partial sum?
find the sum of the series (1/3)^n using partial sums. The sum of the series is 3/2.
how would i go about answering this question?
2 Answers
- 1 decade agoFavorite Answer
Here is one rule:
1 + 1/x + 1/x^2 + 1/x^3 + .... = x/(x-1)
The value of our x will be 3 if we will add the series (1/3)^n
3/(3-1) = 3/2
Try practicing the formula for other stuffs, hope this helps. =D
Example:
1 + 1/2 + 1/4 + 1/8 + 1/16 + ... = 2
- ?Lv 71 decade ago
This is of the form: r^(n) where r = 1/3
Sum = 1 / (1 - r) (if and only if the absolute value of r < 1)
1 / (1 - 1/3) = 1 / (2/3) = 3/2
