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- henry_yang67Lv 61 decade agoFavorite Answer
you can use half angle directly
cos A/2 = -sqrt((1+cosA)/2) = -sqrt(5)/5
the angle A/2 is in Q II so it's negative
- ?Lv 61 decade ago
(1+cosA)/2 =cos^2A/2 sq.root(1+cosA)/2=cosA/2 sq.root(1-3/5)=cosA/2 sq.root(2/5)=cosA/2
A/2 is in 2nd quadrant so -sq.root(2/5)=cosA/2
- Anonymous1 decade ago
A=cos-1{-3.5}
.: A= - cos-1{3.5}
find it from natural cosine table.
so u will get the value of A.
now u can easily find cosA/2.
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