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- henry_yang67Lv 61 decade agoFavorite Answeryou can use half angle directly cos A/2 = -sqrt((1+cosA)/2) = -sqrt(5)/5 the angle A/2 is in Q II so it's negative 
- ?Lv 61 decade ago(1+cosA)/2 =cos^2A/2 sq.root(1+cosA)/2=cosA/2 sq.root(1-3/5)=cosA/2 sq.root(2/5)=cosA/2 A/2 is in 2nd quadrant so -sq.root(2/5)=cosA/2 
- Anonymous1 decade agoA=cos-1{-3.5} .: A= - cos-1{3.5} find it from natural cosine table. so u will get the value of A. now u can easily find cosA/2. 
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