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Exact Value of Tan(300degrees)?
tan2((5pi)/2) = [2 tan((5pi)/2)] / [1 - tan^2 ((5pi)/2)]
= [2 * -sqrt(3)] / [1 - (-sqrt(3))^2
= [ -2sqrt(3) ] / [1 - 3]
= [ -2sqrt(3) ] / [ -2 ]
* -2 cancel each other
= sqrt(3)
shouldn't it be -sqrt(3)?
what did i do wrong?
*correction tan2((5pi)/3) = [2 tan((5pi)/3)] / [1 - tan^2 ((5pi)/3)]
Use double-angle identity
Use double-angle identity
1 Answer
- HemantLv 71 decade agoFavorite Answer
... tan 300°
= tan [ 2(180)° - 60° ]
= tan 60°
= √3 ..................................... Ans.
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