Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
How fast, in rpm, would a 140 g, 60 cm diameter beach ball have to spin to have an angular momentum?
How fast, in rpm, would a 140 g, 60 cm diameter beach ball have to spin to have an angular momentum of 0.14 kg*m^2/s?
please show the work to back it up!
1 Answer
- 1 decade agoFavorite Answer
Well, we know that angular momentum is L= I*w, where I=(moment of inertia) and w=angular frequency. The moment of inertia of a spherical shell is 2/3*M*R^2.
So we know that I=(2/3)(.140kg)*(.3^2).
we'll set L=0.14 kg*m^2/s=(2/3*.140*.09)*w and solve for w.
W is in radians per second, which to get to rpms you'll use the conversion 2*pi radians/revolution and 60 seconds/minute. In other words, multiply w by 50 and divide by 2*pi, and you'll have your answer!
