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simple physics question?
a 0.50 kg ball is thrown vertically upward with an initial kinetic energy of 25 Joules. aproximately how high will the ball rise?
1 Answer
- Anonymous1 decade agoFavorite Answer
KE = 1/2mv^2
The first step is to solve for the initial velocity.
Vf^2 = Vi^2 +2ad
Next, using the kinematic equation above, solve for the distance the ball travels. Vf will be 0 since that will be maximum height. Vi will be the value solved previously and 'a' will be the acceleration (or in this case, deceleration) of gravity(-9.81m/s^2).