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What impact does the addition of heat have on the degree of solubility for an exothermic process?

I'm not understanding this question ... is it asking if I'm cooling down water, and adding heat at the same time, how would it impact the degree of solubility ?

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  • 1 decade ago
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    Your question is asking: Will adding heat to an exothermic process increase or decrease the ability of the reactants to dissolve in solution?

    Remember, an exothermic reaction gives off heat.

    As a follow-up to Josh's answer, Le Chatelier's Principle simply states that when stress is placed on a chemical system, the system will shift in a direction to oppose this added stress. In your case, adding heat places "stress" on the product side because for an exothermic reaction, heat is being released as a product (refer to Josh's equation).

    When heat is added for an exothermic reaction, it is added to the products, causing the reaction to shift to the left (toward the reactants), and thus the solubility will decrease. This is because there are more reactants to consume, so to speak, so their ability to create products is hindered.

    As an example, cooling down water is an exothermic reaction because heat is given off in order to cool the water. Think of it this way: If you add heat to the cooling water, wouldn't it make it harder to create ice? This is an obvious yes. Therefore, solubility decreases because it is harder to create the product (ice).

  • 1 decade ago

    The effect of temperature on the solubility of a solid in water may be predicted using Le Principe du Chatelier if it is known whether the process is endo- or exothermic. If the solution process is endothermic, solubility increases with increasing temperature; if exothermic, solubility decreases. Le Chatelier's Principle permits us to make only qualitative predictions of solubility for a particular solute-solvent system.

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