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H@z@r@h asked in Science & MathematicsPhysics · 1 decade ago

Phenomena on Liquid Surfaces. Help Me Solve This Question?

What work is required to blow a soap bubble 10cm in diameter at 20 Degree Celcius? (Surface Tension = 0.04Jm^-2)

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  • 1 decade ago
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    Assuming that the original area of the soap was negligible then the work done is the area of the bubble multiplied by the surface tension.

    The bubble would be a sphere of radius 0.05 m

    and its area would be 4 pi() r^2

    So the work as far as surface tension would be = 0.04 * 4 * pi() * 0.05 ^2

    = 0.0013 J

    There could be some work involved in compressing the air but this should be negligible relatively.

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