Need Capacitor help please?

I think you left off some exponents. it's 10^9 (I think) not 109, 10^5, not 105. Given that uncertainty, I'll not do any actual calculations but give you all the formula.

Those numbers are very different.

Given that, use the N/C number, which is also volta/meter, with the spacing of 6 mm to get the voltage on the plates. You have the charge, 2.25x109 or whatever it is, and the voltage. Use Q = CV or C = Q/V to calculate the capacitance.

Then use

Parallel plate cap

C = ε₀εᵣ(A/d) in Farads

ε₀ is 8.854e-12 F/m

εᵣ is dielectric constant (vacuum = 1)

A and d are area of plate in m² and separation in m

You have C, and d, so you can calculate A

And from that and A = πr² you can get the radius and then the diameter.

.

certainly a capacitor holds a cost. So while the fan is grew to become on the capacitor says cost the electrons. that is how the motor knows while to tutor on. the human beings here have studied extra electronics then I, and can have a miles better answer.

By V = Qd/ɛA

=>V/d = Q/ɛA

=>E = Q/ɛA

=>A = Q/ɛE

=>A = ne/ɛE

=>A = [2.25 x 10^9 x 1.6 x 10^-19]/[8.85 x 10^-12 x 2.42 x 10^5]

=>A = 1.68 x 10^-4 m^2

=>1/4 x π x d^2 = 1.68 x 10^-4

=>d = √[2.14 x 10^-4]

=>d = 0.0146 m

=>d = 1.46 cm