Solve for x: (2/3X)+5=(4/x)?

2/3x + 5 = 4/x

4/x - 2/3x = 5

Take out common factor of 1/x

1/x (4 - 2/3) = 5

x = (4 - 2/3)/5

x = 10/15

x = 2/3

Hope this helped :)

2 3x 5

QUESTION: Solve for x. EXPRESSION: 5^(4 - x) = 2^(3x +5) SOLUTION: Move 2^(3x +5) over to the other side of the equation, this means that you have to subtract 2^(3x + 5) from 5^(4-x) because the sign changes from positive to negative. 5^(4-x) - 2^(3x+5) = 0 (4-x) and (3x+5) are powers. You cannot add values with different powers, therefore we need to find the LCM of the two. Since variables are envolved, the LCM would be (4-x)(3x+5); the LCM is simply the first power in brackets multiplied by the second power in brackets. [ 5^(4-x) - 2^(3x+5) = 0 ] / (4-x)(3x+5) What you are going to do, is cancel and multiply the base by the opposite superscript. Example 5 has a power of (4-x) therefore you are going to multiply 5 by (3x+5). - 2 has a power of (3x+5) therefore you are going to multiply - 2 by (4-x). base 0 has no power. Anything multiplied by zero is zero, therefore there is no change, it is constant. [ (5)(3x+5) - (2)(4-x) = (4-x)(3x+5)(0) ] / (4-x)(3x+5) Simplify by multiplying, to remove the brackets. [ 15x + 25 - 8 + 2x = 0 ] Groupe similar terms, this envolves re-arrangement of the expression: [ 15x + 2x + 25 - 8 = 0 ] Add similar terms, you can only add constants with constants and variables: [ 17x + 17 = 0 ] Group similar terms again by moving the positive 17 to the opposite side of the equation. The positive 17 becomes negative. [ 17x = 0 - 17 ] Add similar terms again: [ 17x = - 17 ] Divide both sides of the equation by 17 so that the coefficient of x becomes 1 and so that you can find the value of x. [ (1/17)(17x) = (1/17)(- 17) ] x = - 1