Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
How to find the particular sol. for 9y"'+3y"-5y'+1=42(e)power x + 64(e)power x/3?
1 Answer
- cidyahLv 71 decade agoFavorite Answer
9y"'+3y"-5y'+1=42(e)power x + 64(e)power x/3
9y"'+3y"-5y'+1= Ae^x + B e^x/3
y' = A e^x + (1/3) B e^(x/3)
y'' = A e^x + (1/9) B e^(x/3)
y''' = A e^x + (1/27) B e^(x/3)
9[A e^x + (1/27) B e^(x/3)] + 3 [ A e^x + (1/9) B e^(x/3)] -5 [A e^x + (1/3) B e^(x/3)] +1 = 42e^x + 64 e^x/3
Compare coefficients of e^x
9A+3A-5A=42
7A=42
A=6
compare coefficients of e^(x/3)
9B/27+3B/9-5B/3 = 64
(9+9-45)B/27=64
-B=64
B=-64
A=6; B=-64
Yp(x) = 6e^x-64e^(x/3)
is the particular solution.