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What is the molality of ammonia in a solution containg 0.85g of NH3 in 100cm3 of a liquid of density 0.85gcm-3?

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  • Elie D
    Lv 4
    1 decade ago
    Favorite Answer

    Density = 0.85 grams/cm^3 = 0.85 grams/0.001L = 85grams/0.1L

    Every 0.1L of that solution weights 85grams

    There are 0.85 grams of NH3 in 100cm^3 = 0.85grams/0.1 solution

    Mass of water in solution (0.1L) = 85-0.85 =84.15grams =0.08415kg

    Number of moles of NH3 = Mass/Mw of NH3 = 0.85/17=0.05mol

    Molality = Number of moles / mass of water in kg = 0.05/0.08415=0.597 Molal

    Source(s): sharbel_91@hotmail.com if u need more help
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