Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Math problems that I need help in?
Find the derivative of each of the problems
y= 1/square root of x+1
y= tan(pix=1)
y= cos 3x/2
1 Answer
- Scarlet ManukaLv 71 decade agoFavorite Answer
y = 1 / √(x+1) = (x+1)^(-1/2)
So dy/dx = (-1/2) (x+1)^(-3/2).
I'm going to assume the second one is y = tan (πx + 1). If the second = sign was supposed to be something other than a +, make the appropriate corrections to this answer.
y = tan (πx + 1); remember that the derivative of tan x is sec^2 x, so we get
dy/dx = sec^2 (πx + 1) . π
y = cos (3x/2)
dy/dx = -sin (3x/2) . (3/2)