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Given the following solubility, calculate the solubility product of each compound. Please help with chemistry!?
--> Given the following solubilities, calculate the solubility product of each compound.
(a) AgNO2 - 1.55 g/L
(b) Ag2CrO4 - 1.31x10-4M
2 Answers
- steve_geo1Lv 710 years agoFavorite Answer
(b) Ag2CrO4 ===> 2Ag+ + CrO4=
If molar solubility of Ag2CrO4 = 1.31 x 10^-4, then [CrO4=] = 1.31 x 10^-4 and [Ag+] = 2.62 x 10^-4
Ksp = [Ag+]^2[CrO4=] = (2.62x10^-4)^2(1.31x10^-4) = 8.99 x 10^-12
I'll leave the first one to you.
- ChemTeamLv 710 years ago
Convert grams per liter to moles per liter. Do this by dividing the 1.55 g/L by the molecular weight of AgNO2. Then look here:
