How far apart two electrons be,if the force between them equal to the weight of an electrons?

Negleting gravitational attraction from Coulomb's law the force F between the 2 electrons is f=k.(q^2)/d^2 where d is their distance apart and q the electronic charge.

Thus F =mg where m is the electron's mass and g the acceleration of gravity = 9.81 m/s^2.

Or k.(q^2)/d^2 =mg ==> d^2 = k.(q^2)/mg ==> d = sqrt(k.(q^2)/mg) k =Coulomb's conts

Let f = mg = kq^2/r^2; then r^2 = kq^2/mg and r = sqrt(kq^2/mg) = ? is the distance apart you're looking for. Look up k, the constant of proportionality, q = 1.6E-19 C, m = 9E-31 kg, and g = 9.81 m/sec^2. You can do the math. w = mg is the weight of one electron.

hi you're able to wish to stick to Coulomb's regulation: F = one million/ (4 pi e0) Q1Q1/r^2 Q1 = Q2 = one million.6 x 10^-19 e0 = permittivity of unfastened space8.854 x 10^-12 F as given, rearrange for r, remembering to sq. root. this grant you the surprising answer!