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Tim
Lv 4
Tim asked in Science & MathematicsChemistry · 10 years ago

What is the molarity of aqueous lithium bromide if 25.0mL of LiBr reacts with 10.0mL of 0.250M Pb(NO3)2?

Pb(NO3)2 + 2LiBr = PbBr2 +2 LiNO3

A) 0.0500M B) 0.100M C) 0.200M D) 0.250M E) 1.25M

I came up with C) 0.200M but I'm not sure if I am doing this right. Please help.

1 Answer

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  • Lexi R
    Lv 7
    10 years ago
    Favorite Answer

    You are correct.

    moles = molarity x litres

    moles Pb(NO3)2 = 0.250 M x 0.0100 L

    = 0.00250 moles

    1 mole Pb(NO3)2 requires 2 moles LiBr to fully react,

    Therefore moles LiBr needed = 2 x moles Pb(NO3)2

    = 0.00500 moles

    Thus there were 0.00500 moles LiBr in the 25.0 ml

    Molarity = moles / Litres

    M LiBr = 0.00500 mol / 0.0250 L

    = 0.200 M

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