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Calculus help? Multiple choice!!?
A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. 840 feet of fencing is used. Find the maximum area of the playground.
A) 44,100 B)22,050 C) 33,075 D)29,400
if you can explain it will be such a huge help (: thank you!!
2 Answers
- AnnLv 610 years agoFavorite Answer
840 = perimeter = 2y + 3x
2y + 3x = 840
2y = 840 - 3x
y = 420 -1.5x
Area = x*y = x*(420-1.5x) = 420x -1.5x^2
Derive and = to zero:
420 -3x = 0
-3x = -420
x = 140
y =420 -1.5(140)
y =420 - 210
y = 210
140 * 210 = 14*10*21*10=100*14*21=100*294 = 29400
- 10 years ago
Deffinelty C.
You do 840 times 4 because a rectangle has 4 sides.
it will be nearest to 33,075.
Hope that helps!
