Just a quick (simple) phyiscs quesiton i need help on?

Average Acceleration = Change in velocity/Time taken

v1 = 50 kmph = 50*1000/3600 = 125/9 m/s

v2 = 0 m/s

t2-t1 = 5s

Thus avg accl = (0-125/9)/5 = -25/9 m/s² = -2.77 m/s².

Negative sign shows retardation.

Hope you get it :)

Given:- u = 50 km/hr = 50 x 1000/3600 = 13.89 m/s

=>By v = u - at

=>0 = 13.89 - a x 5

=>a = 13.89/5

=>a = 2.78 m/s^2

V1 = 50 km/h = 50000 / 3600 = 13.89 m/s

V2 = 0

so V2 = V1 + at

=> 0 = 13.89 + 5a

=> a = -13.89 / 5 = - 2.78 m/s^2

the minus sign indicates that it's a deceleration .

Can't use formulas unless in m/s

50/3.6 =13.8888889 m/s

this is a kinematic equation if you don't know

v= final velocity

u= initial velocity

a =acceleration

t=time

v= u+at

0=13.88888+5a

-13.888888 =5a

a= -2.78 (aprox I rounded up)

it has to be negative because you're going against initial direction slowing down

eleventy twelve