Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

How do I solve this Algebra problem?

Here is the problem: You want to mat and frame a 5x7 photograph. The perimeter if the outside of the mat is 44 inches. The mat is twice as wide at the top as it is at the sides. Find the dimensions of the mat. (The mat goes outside the frame,almost like a second frame.)

1 Answer

Relevance
  • ?
    Lv 4
    10 years ago
    Favorite Answer

    Let the Outer Length and Breadth be L, B

    (L+B)*2 = Perimeter = 44 => L+B = 22

    Inside Dimensions would be L-3T, B-2T where T is the thickness at the sides of the Mat

    Inside Perimeter = (5+7)*2 = 24

    24 = (L-3T+B-2T)*2 => L+B-5T = 12

    => 5T = 10 => T = 2

    L-3T =7 => L = 13, B-2T = 5 => B = 9

    Dimensions of the Mat

    Outer Length, Breadth = 13, 9

    Inner Length, Breadth = 7, 5

    Thickness at Sides, Top = 2, 4

Still have questions? Get your answers by asking now.