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Calcium hydride reacts with water to form calcium hydroxide and hydrogen gas...?
Calcium hydride reacts with water to form calcium hydroxide and hydrogen gas
how many grams of calcium hydride are needed to form 8.5 grams of hydrogen?
3 Answers
- 10 years agoFavorite Answer
CaH₂ + 2H₂0 --------> Ca(0H)₂ + 2H₂
Calculate the moles of Hydrogen
n = m/mr
8.5/2
= 4.25mol of hydrogen needed
Compare their ratios
CaH₂ : H₂
1 : 2
x : 4.25
x = 2.125mol of CaH₂ needed
Find the molar mass of CaH₂
Ca - 1 x 40 = 40
H - 2x 1 = 2
mr = 42g/mol
Now finally find the mass
m = n x mr
= 2.125 x 42
= 89.25g
- 10 years ago
Balanced chemical equation - 2CaH2 + H2O - 2CaOH + H2
To find the number of moles in hydrogen gas go sample/molar mass of substance
=4.22moles
4.22*2 since ratio of H2 to 2CaH2 is 2 =8.44
Molar mass of calcium hydride is 42.096
To get grams
8.44*42.096=3555.29grams
- 10 years ago
CaH2 + 2H2O = Ca(OH)2 + 2H2
nH2 = 8.5 g/ 2 g/mol = 4.25 mol
nCaH2 = 1/2nH2 = 1/2 x 4.25 mol = 2.125 mol
mCaH2 = 2.125 mol x 42g/mol = 89.25 g
Source(s): General Chem