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Differential Equation question?
I'm a noob when it comes to differential equations so can someone explain how y'=y is ce^x when it is integrated. Is this just a rule or is there actual steps to this?
1 Answer
- hfshawLv 710 years agoFavorite Answer
This is a particularly simple type of first-order differential equation, known as a "separable" equation.
You have:
y' = dy/dx = y
where y = y(x), i.e., it's a function of x.
We can isolate all occurrences of y on one side of the equation and all occurrences of x on the other side by splitting up the derivative into differentials:
dy/y = dx
Now integrate both sides:
ln(y) - ln(c) = x - d
where ln(c) and d are the constants of integration resulting from the two integrations. Note that because these are just constants, we can combine them into a single constant. This is always the case:
ln(y) - ln(C) = x
where ln(C) = d - ln(c) is just another way of writing the constant.
Now combine the logarithmic terms using standard rules for manipulating logs.
ln(y/C) = x
Exponentiate both sides:
y/C = exp(x)
y(x) = C*exp(x)