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Trignometry questions?

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1. Solve : 2 tan x = 4x - 2 sin 2x cos 2x tan² x

2. Show that the solutions of the equation tan ax = tan bx, a² + b² <> 0 are in A.P. Find the common difference of the series.

3. If α , β be the roots of the equation a cos 2θ + b sin 2θ =c then show that

tan α + tan β = 2b / (c + a) and tan α tan β = (c - a) / (c + a)

2 Answers

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  • 10 years ago
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    2.

    tanax = tanbx

    => ax = kπ + bx, k ∈ Z - {0}

    => x = kπ/(a - b), k ∈ Z - {0}

    => x = { ..... -2π(a - b), - π/(a - b), π/(a - b), 2π/(a - b), .....}

    => the solutions for a^2 + b^2 ≠ 0 are in A.P.

    and common difference = π/(a - b)

    3.

    a cos 2θ + b sin 2θ = c

    => a (1 - tan^2 θ) / (1 + tan^2 θ) + 2b tan θ / (1 + tan^2 θ) = c

    => a (1 - tan^2 θ) + 2b tan θ = c (1 + tan^2 θ)

    => (c + a) tan^2 θ - 2b tan θ + (c - a) = 0

    If α , β be the roots of the equation which is a quadratic in tan θ,

    sum of the roots

    = tan α + tan β = 2b/(c + a)

    and product of the roots,

    tan α * tan β = (c - a) / (c + a).

  • 10 years ago

    3. acos2x + bsin2x = c [ take theta = x ]

    a + b tan2 x = c/cos2x

    a + b [2tanx /1- tan^2x ] = c [1+tan^2x/1- tan^2x]

    a [ 1- tan^2x] + b [2tanx] = c[ 1+ tan^2x]

    a - atan^2x + 2b tanx = c + c tan^2x

    tan^2x [a+c ] -- 2b tanx + {c-a} =0

    now as tan alpha & tan beta are roots of this equation

    so some of roots , i.e. tan alpha + tan beta = 2b/(c+a ) PROVED

    and product of roots i. e. tan alpha * tan beta = c-a / c+a PROVED

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