Find the mass of sulfur in the original mixture.?

C+O2--> CO2 ans S+O2 ---> SO2

the mass of CO2 is 12+2*16= 44g the mass of SO2 is32+16*2=64g

The relation of the mass of CO2 relative to C is 44/12=3.667

the relation of mass of SO2 to S is 64/32=2

so you have 2 equations if x is mass of C a y the mass of S

x+y = 9 (1)

3.667x +2y =19.5(2)

you solve (1) gives y =9-x

3.667x +18-2x =19.5

1.667x =1.5

x=0.9g of carbon and y=9-0.9=8.1g of sulfur

Carbon And Sulfur

Very Simple Question

Molar Mass of C (Carbon) = 12 a.m.u.

Molar Mass of S (Sulphur) = 32 a.m.u.

Actual mass of Mixture = 9.0 g

Sum of Molar Masses = 12+32 = 44 a.m.u.

44 a.m.u. of mixture gives weight = 9.0 g

32 a.m.u. of Sulphur will weigh = 32/44*9 = 6.545 g

You see its very simple.Don't get confused by reading combustion....Answer lies in the front just like engines of hatchback cars....LOL.

And if you insist over getting those combustion equations solved...her it is :::

Molar Mass of CO2 = 12+16*2= 44 a.m.u.

Molar Mass of SO2 = 32+16*2= 64 a.m.u.

We got weight = 19.5

then Sulphur in this = 64/44+64 * 19.5 = 64/108*19.5 = 11.5 g

Carbon then = 19.5-11.5 = 8 g

To check if my answer is correct

Make ratio = 11.5/8 = 1.437 = 1.4

Now Divide the ratio with value of S in original mixture or multiply with value of C.You'll get 9.0 g.Then its right answer.

Have a nice day!!!

Co2+so2..

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