Math problem, please answer?

A. Think of the screen as a rectangle with a diagonal line through it forming two triangles; the formula to solve for the diagonal side of a triangle is "a squared + b squared = c squared". The two short sides are a & b. Square them, add together, then find the square root to solve for 'c', which is the diagonal.

B. make a list of squares and find two that add together to give the same result as your example. You will probably need to do some trial and error and use decimals to get close.

a) Using Pythagoras' theorem, diagonal is given by

sqrt(16*16 + 22* 22) = sqrt(740) = 27 to nearest integer

b) There's an infinite number of solutions to this one.

height^2 + width^2 = 740

Choose height = 1, then width = sqrt(740 - 1*1)

Choose height = 2, then width = sqrt(740 - 2*2)

...and so on

Dear Shaylee,

T[,90,,16,22,]

Use the Pythagorean theorem to find the unknown side. In any right triangle, the area of the square whose side is the hypotenuse (the side of a right triangle opposite the right angle) is equal to the sum of areas of the squares whose sides are the two legs (i.e. the two sides other than the hypotenuse).

AC^(2)+CB^(2)=AB^(2)

Solve the equation for AB.

AB=~(AC^(2)+CB^(2))

Substitute the actual values into the equation.

AB=~((16)^(2)+(22)^(2))

Expand the exponent (2) to the expression.

AB=~((16^(2))+(22)^(2))

Squaring a number is the same as multiplying the number by itself (16*16). In this case, 16 squared is 256.

AB=~((256)+(22)^(2))

Expand the exponent (2) to the expression.

AB=~((256)+(22^(2)))

Squaring a number is the same as multiplying the number by itself (22*22). In this case, 22 squared is 484.

AB=~((256)+(484))

Remove the parentheses that are not needed from the expression.

AB=~(256+484)

Add 484 to 256 to get 740.

AB=~(740)

Pull all perfect square roots out from under the radical. In this case, remove the 2 because it is a perfect square.

AB=2~(185)=27.2029 inches

-----------------------------

T[,90,,,24,27.2029]

Use the Pythagorean theorem to find the unknown side. In any right triangle, the area of the square whose side is the hypotenuse (the side of a right triangle opposite the right angle) is equal to the sum of areas of the squares whose sides are the two legs (i.e. the two sides other than the hypotenuse).

AC^(2)+CB^(2)=AB^(2)

Solve the equation for AC.

AC=~(AB^(2)-CB^(2))

Substitute the actual values into the equation.

AC=~(27.2029^(2)-24^(2))

Squaring a number is the same as multiplying the number by itself (27.2029*27.2029). In this case, 27.2029 squared is 739.9978.

AC=~(739.9978-24^(2))

Squaring a number is the same as multiplying the number by itself (24*24). In this case, 24 squared is 576.

AC=~(739.9978-576)

Subtract 576 from 739.9978 to get 163.9978.

AC=~(163.9978)

Take the square root of 163.9978 to get 12.8062.

AC=12.8062

a^2+b^2=c^2

16^2+22^2=c^2

256+484=c^2

740=c^2

c=27

a^2+b^2=740 just pick a number for a and solve for b

12^2+b^2=740

b^2=740-144

b^2=596

b=24

Hello,

Nice to see you again Miss Shaylee. Welcome back sweet girl

A)

Another a^2+b^2=c^2.....................a=16............b-22.................find diagonal c

c^2=a^2+b^2

c^2=16^2+22^2

c^2=256+484

c^2=740

sqrtc^2=sqrt740

c=27.2................. or c=27in..............to nearest integer....ANSWER

B)..........OOOooooo a tuffy.......i thought you liked me.......now you are making me think

AAAHHHhhhhhh but the problem did NOT say the your measurements had to be integers

got you now..................

Let a=sqrt 400............b=sqrt 340................since 400+340 add to 740

c^2=[a]^2+[b]^2

c^2=[sqrt400]^2+[sqrt340]^2

c^2=400+340

c^2=740

sqrtc^2=sqrt740

Bring it on sweet lady....bring it on

c=27.2................. or c=27in..............to nearest integer

ANSWERS...........a=sqrt400=20...........b=sqrt340=2sqrt85

I guess in both cases its dim = 1

not sure though