Algebra 1 question, probably easy (URGENT!!!!!!)?

You move the ps to one side, and the numbers to the other :)

-2/5p - 1/5p = 11 - 2

-3/5p = 9

-3 = 45p

p = -15

I hope this helps. :)

It doesn't matter which side you start with, but many math teacher like to keep the variables on the left.

First, you'd subtract 1/5p from both sides to get -3/5p+2=11, then subtract 2 from both sides to get -3/5p=9. Divide both sides by -3/5 or multiply by -5/3 to get

p=-15.

Hope this helped :D Good luck!

You can go either way

First I'll move the p's to the left

-2/5p + 2 = 1/5p + 11

-2/5p - 1/5p = 11 - 2

-3/5p = 9

p = 9 * (-5/3) = -45/3 = -15

Now I'll move the p's to the right

-2/5p + 2 = 1/5p + 11

2 - 11 = 1/5p + 2/5p

-9 = 3/5p

p = -9 * 5/3 = -45/3 = -15

See, it works either way!!

I would do it like this.

-2/5p +2 = 1/5p+11

minus 1/5p both sides

-3/5p+2 = 11

minus 2 both sides

-3/5p = 9

divide both sides by -3/5

p = -15

now i would check by putting -15 in for p use parenthesis () when substituting.

I checked it on my calculator and it all works out p = -15

-2/5p + 2 = 1/5p + 11

2 = (3/5)p + 11 {added (2/5)p to both sides}

-9 = (3/5)p {subtracted 11 from both sides}

p = -15 {divided both sides by 3/5, multiplying by reciprocal, 5/3}

http://www.algebrahouse.com/

Is it (-2/5)p or -2/(5p)? Same thing with the other one. Is it (1/5)p or 1/(5p)? Are the p's in the denominator?

JUST MULTIPLY BY 5 BOTH SIDES

-2p + 10 = p + 55

3p = -45

p = -15 ANSWER