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statistics golf problem?
The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards ( Golfweek , March 29, 2003). Assume that the driving distance for these golfers is uniformly distributed over this interval.
What is the probability the driving distance for one of these golfers is less than 290 yards (to 4 decimals)?
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What is the probability the driving distance for one of these golfers is at least 300 yards (to 4 decimals)?
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What is the probability the driving distance for one of these golfers is between 290 and 305 yards (to 4 decimals)?
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How many of the 100 golfers drive the ball at least 290 yards?
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1 Answer
- M3Lv 710 years agoFavorite Answer
the full interval (310.6-284.7) = 25.9 will form the denominator for calculating Pr
the stipulated range will form the numerator, eg
P(<290) = (290-284.7)/25.9 = .2046 <---------
the 1st 3 q's are to be solved in exactly the same way
[expected # of golfers ≥ 290) = 100(1-.2046) = 79.54, ie 80, say <---------
