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How to find dy/dx of (x^2)y=1 explicitly?

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  • 10 years ago
    Favorite Answer

    x^2=y

    2xdx=dy

    dy/dx=2x

    dx/dy=1/2x

  • 10 years ago

    it is simple my frend... just take x^2 in RHS means.. y=1/x^2 then apply d/dx on whole side which means dy/dx=d/dx 1/x^2 then write 1/x^2 as x^-2 and differentiate with the formula y=x^a...... dy/dx= ax^a-1

    :) understand!!

    Source(s): my mind!!
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