Physics question... refraction of light at a plane surface?

There are two angles of emergence, one is the wave refracting off the glass from the water and the second is from the glass back to the water.

n2/n1 = sin i / sin r

where n2 is the refractive index of the second medium

n1 is the refractive index of the first medium

i = angle of incidence (degrees)

r = angle of emergence (or refraction)

Also by using your rules inside the prism, you will find the angle of incidence is 60 degrees. Each angle of the triangle corners is 60 degrees also.

1.45/1.33 = sin 60/sin r

sin60 x 1.33/1.45 = 0.79 = sin r

sin^-1 (-0.28) = r

r = 52.6 degrees

Okay so now the light is inside the glass prism. I also worked out that the next angle of incidence to be 37.4 degrees.

Therefore:

sin 37.4/sin r = 1.33/1.45

sin r = sin37.4 x 1.45/1.33

sin r = 0.66

r = sin^-1 (0.66)

= 41.66 degrees

Therefore the light emerges from the prism at an angle of 41.66 degrees.

Am I right?