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A committee of 5 persons is to be chosen from a group of 5 men and 10 women in a random manner.?
Ok, so this is question from an old midterm at UCLA's EE131A class. Thanks for helping to prove the solution.
a. Find the probability that the committee will have 2 men and 3 women.
b. Find the probability that the committee will have all women.
The total number of combinational outcomes of 5 person from a group of 15 persons in the committee
is Combination: C(15,5) [15!]/[10! 5!]
1 Answer
- Anonymous10 years agoFavorite Answer
a) (5C2)*(10C3)/(15C5)
b) (10C5)/(15C5)