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question on formula of ionic compounds?
what is the formula of these ionic compounds?
C=Cation A=Anion
1. C= Cu+2 A=CO3 -2
2. C= Cu+2 A=Cl-1
3. C= Cu+2 A= OH-1
4. C= Cu+2 A= PO4 -3
5 C= Fe+3 A= CO3 -2
6. C= Fe+3 A= Cl-1
7 C=Fe+3 A=OH-1
8 C=Fe+3 A= OH-1
9 C=Pb+2 A= CO3 -2
10 C=Pb+2 A= Cl-1
11 C=Pb+2 A=OH-1
12 C=Pb+2 A= PO4 -3
1 Answer
- 10 years agoFavorite Answer
You have to switch the charges given. If they have the same charges you don't write them, because they cancel. Also don't write charges of 1.
1. Cu2(CO3)2
2. CuCl2
3. Cu(OH)2
4. Cu3(PO4)2
5. Fe2(CO3)3
6. FeCl3
Get it? You should try the other ones. It is super easy.
The ones in parenthesis are polyatomic ions, so they must be grouped together and when you switch the charge, the charge applies to the whole group, so it goes out side the parenthesis, like it is waiting to be distributed.
