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A spherical water drop of 1 mm in diameter splits up into 64 smaller drops of equal size. What the work requi?
The question is
What the work required ?
2 Answers
- Greg GLv 510 years agoFavorite Answer
We can determine the change in the total surface energy by knowing the surface tension of the water. Assuming 25 degC, the surface tension of water is 71.97 dyn/cm = 71.97mN/m
The initial surface energy is 4pi(.5mm)^2 * (71.97 mN/m) = 2.261*10^-4 mJ
The total volume of the smaller drops must equal that of the larger drop.
(.5mm)^3 = 64*r^3 --> r = .125mm
The new total surface energy is:
64*(4pi)*(.125mm)^2 * (71.97 mN/m) = 9.044*10^-4 mJ
This represents an energy difference (work required) of 6.783*10^-4 mJ
