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Buster
Lv 6
Buster asked in Science & MathematicsMathematics · 10 years ago

Need Help with this algebra question:?

A 25foot ladder is leaning against a building. If the bottom of the ladder is 15ft from the base of the building, how high does the ladder reach. Please show me how to solve this.

Thanks

3 Answers

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  • John
    Lv 4
    10 years ago
    Favorite Answer

    It's not algebra it's trigonometry. Google right triangles.

  • Anonymous
    10 years ago

    a^2+b^2=c^2. a^2 is the base, or distance ladder is away from wall, so 15^2=225. c^2 is the ladder leaning, and it's 25ft, so c^2-> 25^2. you have 225+b^2=625. b^2=400, b=20 ft high.

  • wirehawkboston
    Lv 7
    10 years ago

    Pythagorean triangle

    a^2 + b^2 = c^2

    15^2 + b^2 = 25^2

    225 + b^2 = 625

    b^2 = 400

    b = 20

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