physics question nt sure?

Your description is not too clear, but I'm assuming that there is a vertical wall and a flower pot is being suspended with a string that is attached to the wall. The string goes from some point on the the wall to the centre of the pot which is up against the wall. The further up the wall from the pot that the string is attached causes the ange of the string to the wall to decrease.

If that's the case, then the tension in the string does increase as the angle gets bigger. That's because the weight of the pot is being supported only by the string, and the force vector has to point along the line of the string. Only the vertical component of that vector supports the weight. So the formula for the tension in the string is T = W / cos(a), where T = string tension, W = pot weight and a = angle between string and wall.

Yes it is true.Suppose the string makes an angle A with the wall amd M is the mass of the Pot.So by resolving forces we see that

T.cos.A=Mg

T=Mg/cos.A

if A=0 then T=mg

A=45 T=root(2).Mg

A=60 T=2Mg

so we see that larger the angle the more is the tension.

I made a relevant figure

http://www.flickr.com/photos/70028742@N04/63611424...

Keep in mind that the resolved components are mutually perpendicular.