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If the vectors A and B have magnitudes of 10 and 11, respectively, and the scalar product of these two vectors?
If the vectors A and B have magnitudes of 10 and 11, respectively, and the scalar product of these two vectors is –100, what is the angle between the two vectors when they are drawn starting from the same point?
Answer 155°
90°
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2 Answers
- Anonymous9 years agoFavorite Answer
10*11*cos(theta)=-100
cos(theta)= -100/110
theta= cos-1(-100/110)
theta= 155
- 9 years ago
Use the formula ABcos(angle) = A * B (where A * B is the dot product) then you use the inverse cos((A*B)/AB). Your answer should come out to be 155.3 degrees.
Source(s): I'm double majoring in Engineering & Chemistry with a minor in math, I've been to a science and math school, and I'm in Calc 3 during the first semester of my freshmen year of college.
