Programming language C: Converting int to string?

You can use sprintf.

For example, if L=8, then a format string of "%08d" will print eight digits with leading zeroes. You can use another sprintf to construct the format string:

char fmt[10];

char res[10];

sprintf(fmt, "0%dd", L ); // Create %0[L]d format string

sprintf(res, fmt, yourNumber ); // Use the format

@M

your application seems to basically be changing a single digit of decimal into hexadecimal (form of extra of merely renaming 10 - 15 A - F) particularly than going from hexadecimal to decimal in case you had to bypass from hexadecimal to decimal you need to do some thing alongside the lines of int A = 10, B = 11, ...; then take the enter that they provide you and then have cin >> hexa; n = digit; deci += hexa * pow(sixteen, n); utilising a loop to verify you get each and every digit or some thing in case you already know the type of digits you are able to start from the utmost one or you're able to desire to start from the backside one till you go with for to get the entire enter first

sprintf is your friend in this case

http://www.cplusplus.com/reference/clibrary/cstdio...

look up the 0 specifier in flags and * in the width specifiers

this is an easy example:

#include <stdio.h>

int main(void){

int j=4437;

int L;

L=7;

char res[20];

sprintf(res,"%0*d",L, j);

printf("%s",res);

return 0;

}