Find a: 6a + 10 = 4a + 16?

6a + 10 = 4a + 16

6a - 4a = 16 - 10

2a = 6

a = 3

put all the 'a' numbers on one side of the equation. so minus 4a from the the left side and the right side so it becomes 6a - 4a + 10 = 16. Then put all the other numbers on the other side. so minus 10 on both sides. looks like this 6a - 4a = 16 - 10. then it becomes 2a = 6. then divide both sides by 2 so it's 2a/2 = 6/2 so it's a = 3.

You want to get all of the a's on one side, and all the constants (normal numbers) on the other.

6a+10 = 4a + 16

*Subtract 4a from both sides

2a+10 = 16

*Subtract 10 from both sides

2a = 6

*Divide both sides by 2

a = 3

6a + 10 = 4a + 16

Subtract 4a from both sides

2a + 10 = 16

subtract 10 from each side

2a = 6

divide both sides by 2

a = 3

6a + 10 = 4a + 16

6a -4a = 16 -10

2a = 6

a = 6/2 = 3

6a+10=4a+16

Subtract 4a from both sides than subtract 10 from both sides you would get 2a=6 divide both sides by 2 and a=3!

a = 3

6a + 10 = 4a + 16

6a - 4a = 2a

2a+10=16

16 - 10 = 6

2a = 6

6 / 2 = 3

6a-4a+10=4a-4a+16

2a+10=16

2a+10-10=16-10

2a=6

2a/2=6/2

a=3

plug 3 in for "a" and it checks

28=28

6a - 4a = 16 - 10

2a = 6

a = 6/3

a = 2

You shouldnt be Asking us to DO YOUR WOrk for you but to help you. What i would do is subtract 10 on both sides. then subrtact 4 on both sides so that leaves you with 2a=6 then divide 2 from 6 which leaves a=3