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Block A, with a mass of 2 kg, moves along the x axis with a velocity of 5 m=s in the positive x direction. It?
Block A, with a mass of 2 kg,
moves along the x axis with a velocity of 5 m=s in the positive x direction. It su®ers an elastic collision with block B, initially at rest, and the two blocks leave the collision along the x axis. If the mass of B is much more than the cmass of A, the speed of A after the collision is:
Answer:
- 5 m/s
+10 m/s
0
-10 m/s
2 Answers
- 9 years agoFavorite Answer
Answer is -5 m/s
imagine block B is like a wall. If you throw a ball towards a wall it will bounce back with a velocity opposite to the direction of initial velocity. Similar is the case here, Block B being much more heavier than Block A and will do the same thing as a wall.
hope this helps,
:)
- PearlsawmeLv 79 years ago
In elastic head on collision,
The sum of the velocities before and after collision of A will be equal to the final velocity of B
And If mass of B > mass of A, A should rebound.
Hence + 10 and 0 are not the answers.
And the final velocity of A cannot be greater in magnitude than its initial velocity
Hence -10 is also wrong.
The only answer -5 may be correct.
Adding 5 + (-5 ) = 0.
Since the mass of B is very much greater than A ,the mass B is rest even after collision and this is possible.
Hence the answer – 5 is correct.
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