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what is [(x/2)-(2/x) ]over [(1/2)+(1/x)] simplified?
Pre-cal, I have no clue what i'm doing!!
3 Answers
- ?Lv 59 years agoFavorite Answer
[(x²-4)/2x]
-------------
[(x+2)/2x]
=
(x²-4)
-------
(x+2)
=
(x-2)(x+2)
--------------
(x+2)
= (x-2)
- TCLv 79 years ago
[(x/2)-(2/x) ] / [(1/2)+(1/x)]
for numerator the common denominator is 2x so
[(x/2)(x/x)-(2/x(2/2)) ] / [(1/2)+(1/x)]
(x^2/2x - 2x/^2) / ((1/2 + 1/x))
((x^2 - 2x)/2x) / ((1/2 + 1/x))
for the denominator the common denominator is 2x so
((x^2 - 2x)/2x) / (1/2(x/x) + 1/x(2/2))
((x^2 - 2x)/2x) / (x/2x + 2/2x)
((x^2 - 2x)/2x) / ((x + 2)/(2x))
now take reciprocal and multiply
((x^2 - 2x)/2x) * 2x/(x + 2)
(x^2 - 2x)/(x + 2)
