Solving for Variable?

This formula is not correctly derived from the original:

I = ((100 x (S/N) - 5) / L) - 2B - (E/4)

Original:

S = ((((I + (2 x B) + (E/4)) x L)/100) + 5) x N

divide N from both side ==> N cannot be 0

S/N = (((I + (2 x B) + (E/4)) x L)/100) + 5

move 5 to left side

(S/N) - 5 = ((I + (2 x B) + (E/4)) x L)/100

multiply 100 on both side

(S x 100 / N) - (5 x 100) = (I + (2 x B) + (E/4)) x L

(S x 100 / N) - 500 = (I + (2 x B) + (E/4)) x L

divide L from both side ==> L cannot be 0

((S x 100) / (N x L)) - (500 / L) = I + (2 x B) + (E/4)

move 2 terms and leave only I on right side

((S x 100) / (N x L)) - (500 / L) - (2 x B) - (E/4) = I

so

I = ((S x 100) / (N x L)) - (500 / L) - (2 x B) - (E/4)

plug in: S = 49 N = 1.1 L = 50 E = 0 B = 35

I = ((49 x 100) / (1.1 x 50)) - (500 / 50) - (2 x 35) - (0/4)

I = (4900 / 55) - 10 - 70 - 0

I = (4900 / 55) - 80

I = 9.090909090909090909090909090909

numbers a million and 2 are already solved for the given variable...? 3) 3a + 2b = c 2b = c - 3a b = (c-3a) / 2 flow words to opposite sides of the equivalent sign with the help of adjusting sign. you prefer to isolate the term that has the variable you're fixing for, that's why I moved 3a to the different part. Then to do away with a coefficient (variety in front of variable), divide the two sides with the help of that variety. the respond ought to truly be written as a fragment with c-3a on the perfect of the fraction and 2 below. 4) mnp + q = ? it is not an equation...there is o equivalent sign and what's on the different part?