geometrical progression?

There are multiple answers to this question.

~David

a relentless is a quantity so as that there is not any n or the different variable invovled. Tn=2^(n+3) and changing n by technique of (n-a million) supplies Tn-a million = 2^(n+2). Tn/Tn-a million = 2^(n+3)/2^(n+2)=2^a million=2, that's a relentless as a results of fact 2^p/2^q=26(p-q). So the form is geometric with user-friendly ratio r=2. additionally the 1st term T1 =a=2^4=sixteen. b) locate S5 and S12 making use of Sn=a(r^n - a million)/(r-a million) = sixteen(2^n-a million) the mandatory sum is S12 - S5 which could provide 65024

Term # Term

--------- -------

1 2.5

2 5

3 7.5

4 10

5 12.5

6 15

7 17.5

8 20