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Daniel
Daniel asked in Science & MathematicsMathematics · 9 years ago

Determine the derivative of y = ((x^5/3)/5) - ((x^4/3)/2)?

6 Answers

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  • Anonymous
    9 years ago
    Favorite Answer

    sol:- dy/dx=5/15(x^2/3)-4/6(x^1/3)

  • Anonymous
    9 years ago

    y' = (1/3) x^(2/3) - (2/3) x^(1/3)

  • MechEng2030
    Lv 7
    9 years ago

    Recall that d/dx[x^(n)] = n*x^(n - 1). From this:

    dy/dx = (1/5)(5/3)*x^(5/3 - 1) - 1/2(4/3)*x^(4/3 - 1)

    dy/dx = 1/3*x^(2/3) - 2/3*x^(1/3)

  • Anonymous
    9 years ago

    Y' = 1/3 (x^2/3) - 2/3 (x^1/3)

    Just differentiate both side & u r done!

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  • kat
    9 years ago

    rewrite your equation:

    x^5/[3(5)] - x^4/[3(2)]

    5x^4/[3(5)] - 4x^3/[3(2)]

    x^4/3 - 2x^3/3

  • Anonymous
    9 years ago

    you really have to do your bit first and expand the brackets and get the coefficients before integrating at all ...

    i can only give you the hint for this .. integral of x^n ---> [x^(n+1)]/(n+1), obviously multiplied by the coefficients before the variables

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