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What is the sulfate ion concentration in a 12 M aqueous solution of Mn(SO4)2?

24M

36M

12M

48M

2 Answers

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  • 9 years ago
    Favorite Answer

    The molar mass of Mn(SO₄)₂ is 247.0645 g/mol!

    To prepare a 12 M solution you would have to dissolve 2964 g of it in a final volume of 1000 ml. Seems to be impossible to me.

    But anyway, each Mn-Sulfate splits into 1 Mn⁴⁺ and two SO₄²⁻ ions. So sulfate ion concentration will be always twice the Mn(SO₄)₂ concentration on molar basis. 24 M is the right answer.

  • 9 years ago

    24M

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