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A question on projectile motion?
A ball is shot from a cannon on a hill that is 1.93m high and lands 17.34m away after 1.586. What was the initial velocity of the ball?
Please help me solve this! Thanks! And I would really appreciate it if you provide me with explainations as well! :D
Amendment: 1.586s
The ball is not shot horizontally from the cannon :)
2 Answers
- JullyWumLv 79 years agoFavorite Answer
Assuming that ..
• The cannon is fired horizontally ..
• Air resistance is negligible .. so the horizontal firing velocity (Vh) is unchanged throughout the flight
• Ball lands 17.34m as a horizontal distance (Dh) from firing point
Horiz.velocity, Vh = Dh / t .. .. 17.34m / 1.586s .. .. .. ►Vh = 10.93 m/s
- DozoLv 69 years ago
Use the travel time to calculate how large the vertical velocity was. Then use the horizontal distance travelled to determine the horizontal velocity. Combine the two velocities into a total vector value.