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A question on projectile motion?

A ball is shot from a cannon on a hill that is 1.93m high and lands 17.34m away after 1.586. What was the initial velocity of the ball?

Please help me solve this! Thanks! And I would really appreciate it if you provide me with explainations as well! :D

Update:

Amendment: 1.586s

Update 2:

The ball is not shot horizontally from the cannon :)

2 Answers

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  • 9 years ago
    Favorite Answer

    Assuming that ..

    • The cannon is fired horizontally ..

    • Air resistance is negligible .. so the horizontal firing velocity (Vh) is unchanged throughout the flight

    • Ball lands 17.34m as a horizontal distance (Dh) from firing point

    Horiz.velocity, Vh = Dh / t .. .. 17.34m / 1.586s .. .. .. ►Vh = 10.93 m/s

  • Dozo
    Lv 6
    9 years ago

    Use the travel time to calculate how large the vertical velocity was. Then use the horizontal distance travelled to determine the horizontal velocity. Combine the two velocities into a total vector value.

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